Complete ADP paper

Q.No.: 5
Question : CALUMNY::ASPERSIONS
 A: Approbation: praise
B: Slander:mockery
C: approval: criticism
D: Expectations: threats

Answer: A
           

Q.No.: 21
Question : A can do a piece of work in 36 days, B in 54 days and C in 72 days. All of them began together but A left 8 days and B left12 days before the completion of the work. How many days in all did C put in till the entire work was finished?
A: 48 days
B: 24 days
C: 18 days
D: 12 days

Answer: B
Solution
Let work gets completed in x days
then A worked for x-8 days
then B worked for x 12 days
then C worked for x days
(x 8)/3 6+(x-12)/54+x/72=1
x=24


Q.No.: 22

Question : A person travels through 5 cities - A, B, C, D, E. Cities E is 2 km west of D. D is 3 km north-east of A. C is 5km north of B and 4 km west of A. If this person visits these cities in the sequence B - C - A - E - D, what is the effective distance between cities B and D?

A: 13
B: 9 km
C: 10 km
D: 20

Answer A
Q.No.: 23

Question :The horizontal distance of a kite from the boy flying it is 30 m and 50 m of cord is out from the roll If the wind moves the kite horizontally at the rate of 5 km per hour directly away from the boy, how fast is the cord being released?
A: 3 kmph
B: 4 kmph
C: 5 kmph
D: 6 kmph
Answer: A
Solution
Method 1:
z2 = x2 + y2
Z = - N P
dz/dt = 2x/(2R -T7) dx/dt as y is constant
Initially x = 30m, y = 40ny dx/dt = 5km/hr
dz/dtj, j I = 2 * 30/(2*50) * 5 = 3 kmph

Method 2:
Initial position of kite:
x= 30
y= 40
z= 50

Alter I hr..Hind made the kite mn,e Skindvectly awa, trcm the he, so, nocitrn of kite 6/17
after 1 second:
x= 30 + 1.39=31.39(because ofwind, 5kmph= 1.39m's)
y= 40
z 4( 31.39*31.39+40*40) = 50.846
Now in 1sec, cord has moved 0.846m=> 3kmph
So, cord is released at the rate of 3kmph.

Q.No.: 24

Question :Two liquids A and B are in the ratio 5 : 1 in container 1 and in container 2, they are in the ratio 1 : 3. In what ratio should the contents of the two containers be mixed so as to obtain a mixture of A and B in the ratio 1 : 1?
A: 2:3
B: 4:3
C: 3:2
D: 3:4
Answer: D
Solution
In 1 lit Container 1 contains 5/6 lit A and 1/6 lit B
In 1 lit Container 2 contains 1/4 lit A and 3/4 lit B
Suppose x lit of I and y lit of 2 are mixed.
So in the mixture A= 5/6x+ l/4y
B= 1/6x+3/4y
According to question,
5/6x+1/4y= 1/6x+3/4y
orxy=3:4

Q.No.: 25

Question : A closed wooden box of thickness 0.5 cm and length 21 cm, width 11 cm, and height 6 cm, is panted on the inside. The cost of painting is Rs 70. What is the rate of painting in rupees per sq. cm?
A: 0.7
B: 0.5
C: 0.1
D: 0.2
Answer. C

Q.No.: 26
Question : If a number 774958A96B is to be divisible by 8 and 9, the values of A and B, respectively, will be:
A: 7,8
B: 8,0
C: 5,8
D: None of these

Answer: B
Solution

If the digit is divisible by 8 then, its last three number should be divisible by 8...
So, possibility of B's value is either 0 or 8.
Its divisible by 9 ifthe sum ofthe digits is : A+55+B
ifB=O : A+55 should be divisible by 9: A=8 (or A+55 -.> A+5+5->A+10-.>A+1)
ifB=8, A+9 should be divisible by 9, A=0
Possible values ofA, B are (8,0) and (0,8).

Q.No.: 27
Question :The price of a Manrti car rises by 30% while the sales of the car came down by 20%. What is the percent change in the total revenue?
A: +4
B: -2
C: -4
D: +2

Answer: A
Solution
Let the Price of a car be x and y cars are sold.
Now New price = 1.3x
and no of car sold = .8y
New revenue = 1.04xy
Old revenue xy
Percentage Increase 4% Ans

Q.No.: 28
uestion : A man travels three-fifths of distance AB at a speed of 3a, and the remaining at a speed of 2b. If he goes from B to A and back at a speed of 5c in the same time, then:
solution
AB = x => AC = 3x/5 and CB = 2x/5.
Distance = Speed * Time
Time taken to travel the distance between A and C = 3x/5 = 3a * Ti => Tl = x/5a
Time taken to travel the distance between C and B = 2x/5 = 2b * 12 => T2 = x/5b
Time taken to travel between A and B back and fourth = x= 5c * T => T = x/5c
Given that, T = Ti + T2
_> x/5a + x/5b = x/5c
=> 1/a+ 1/b = 1/c. 

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